Friday, March 4, 2016

LeetCode Q96: Unique Binary Search Trees

Given n, how many structurally unique BST's (binary search trees) that store values 1...n?
For example,
Given n = 3, there are a total of 5 unique BST's.
   1         3     3      2      1
    \       /     /      / \      \
     3     2     1      1   3      2
    /     /       \                 \
   2     1         2                 3

Solution:
Different from Unique Binary Search Trees II problem, in this problem, there is no need to know exact information contained in each node. All we need to know is for a given number of nodes, how many different unique BST can be generated. The solution is very similar to Fibonacci sequence problem.


class Solution {
public:
int helper(int Num, vector<int>& map){
if(map[Num]!=0)
return map[Num];
int num=0;
for(int i=1; i<=Num; i++){
int n0=helper(i-1, map);
int n1=helper(Num-i, map);
num+=n0*n1;
}
map[Num]=num;
return num;
}
int numTrees(int Num) {
vector<int> map(Num+1, 0);
map[0]=1;
map[1]=1;
int num=helper(Num, map);
return num;
}
};

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