Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST's shown below.
Given n = 3, your program should return all 5 unique BST's shown below.
1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3
Solution (Divide and Conquer)
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/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
vector<TreeNode*> helper(int start, int end){ | |
vector<TreeNode*> allTrees; | |
if(start>end||end<start||start==end){ | |
TreeNode* root=NULL; | |
if(start==end) | |
root=new TreeNode(start); | |
allTrees.push_back(root); | |
return allTrees; | |
} | |
for(int i=start; i<=end; i++){ | |
vector<TreeNode*> ltrees=helper(start, i-1); | |
vector<TreeNode*> rtrees=helper(i+1, end); | |
for(int l=0; l<ltrees.size(); ++l){ | |
for(int r=0; r<rtrees.size(); ++r){ | |
TreeNode* root=new TreeNode(i); | |
root->left=ltrees[l]; | |
root->right=rtrees[r]; | |
allTrees.push_back(root); | |
} | |
} | |
} | |
return allTrees; | |
} | |
vector<TreeNode*> generateTrees(int n) { | |
vector<TreeNode*> allTrees; | |
int start=1; | |
int end=n; | |
for(int i=1; i<=n; i++){ | |
vector<TreeNode*> ltrees=helper(start, i-1); | |
vector<TreeNode*> rtrees=helper(i+1, end); | |
for(int l=0; l<ltrees.size(); ++l){ | |
for(int r=0; r<rtrees.size(); ++r){ | |
TreeNode* root=new TreeNode(i); | |
root->left=ltrees[l]; | |
root->right=rtrees[r]; | |
allTrees.push_back(root); | |
} | |
} | |
} | |
return allTrees; | |
} | |
}; |
Round2 solution
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class Solution { | |
public: | |
vector<TreeNode*> helper(int s, int e){ | |
vector<TreeNode*> res; | |
if(s>e){ | |
TreeNode* tmp = NULL; | |
res.push_back(tmp); | |
return res; | |
} | |
for(int i=s; i<=e; i++){ | |
vector<TreeNode*> left = helper(s, i-1); | |
vector<TreeNode*> right = helper(i+1, e); | |
for(int l=0; l<left.size(); l++){ | |
for(int r=0; r<right.size(); r++){ | |
TreeNode* root = new TreeNode(i); | |
root->left = left[l]; | |
root->right = right[r]; | |
res.push_back(root); | |
} | |
} | |
} | |
return res; | |
} | |
vector<TreeNode*> generateTrees(int n) { | |
vector<TreeNode*> res; | |
if(n==0) | |
return res; | |
res = helper(1, n); | |
return res; | |
} | |
}; |
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