Given a binary tree, return the preorder traversal of its nodes' values.
For example:
Given binary tree
Given binary tree
{1,#,2,3}, 1
\
2
/
3
return
[1,2,3].
Note: Recursive solution is trivial, could you do it iteratively?
Round 2 solution:
Very similar to inorder traversal, but save element when first meet.
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