Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree
Given binary tree
{1,#,2,3}
,1 \ 2 / 3
return
[1,3,2]
.
Note: Recursive solution is trivial, could you do it iteratively?
Solution 1 (Recursive)
Solution 2 (Non-recursive)
Round 2 solution:
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