Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
1 / \ 2 2 / \ / \ 3 4 4 3
But the following is not:
1 / \ 2 2 \ \ 3 3Solution 1: Recursive solution.
Similar to question of check whether two trees are identical. Here, the difference is the order we access the left and right sub-trees of two trees.
Solution 2: Iterative solution.
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