Monday, March 14, 2016

LeetCode Q133: Clone Graph

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.

OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.
Visually, the graph looks like the following:
       1
      / \
     /   \
    0 --- 2
         / \
         \_/
/**
* Definition for undirected graph.
* struct UndirectedGraphNode {
* int label;
* vector<UndirectedGraphNode *> neighbors;
* UndirectedGraphNode(int x) : label(x) {};
* };
*/
class Solution {
public:
unordered_map<UndirectedGraphNode*, UndirectedGraphNode*> hash;
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
if (!node) return node;
if(hash.find(node) == hash.end()) {
hash[node] = new UndirectedGraphNode(node -> label);
for (auto x : node -> neighbors) {
(hash[node] -> neighbors).push_back( cloneGraph(x) );
}
}
return hash[node];
}
};

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