Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is
1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
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/** | |
* Definition for singly-linked list. | |
* struct ListNode { | |
* int val; | |
* ListNode *next; | |
* ListNode(int x) : val(x), next(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
void deleteNode(ListNode* node) { | |
if(node==NULL) | |
return; | |
while(true){ | |
node->val = node->next->val; | |
if(node->next->next==NULL){ | |
node->next=NULL; | |
break; | |
} | |
node=node->next; | |
} | |
} | |
}; |
Round 2 solution:
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/** | |
* Definition for singly-linked list. | |
* struct ListNode { | |
* int val; | |
* ListNode *next; | |
* ListNode(int x) : val(x), next(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
void deleteNode(ListNode* node) { | |
if(node==NULL) | |
return; | |
ListNode* p = node; | |
ListNode* next=p->next; | |
while(next->next!=NULL){ | |
p->val = next->val; | |
p = next; | |
next = p->next; | |
} | |
p->val = next->val; | |
p->next = NULL; | |
} | |
}; |
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