Given a non-negative integer
num
, repeatedly add all its digits until the result has only one digit.
For example:
Given
num = 38
, the process is like: 3 + 8 = 11
, 1 + 1 = 2
. Since 2
has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
Could you do it without any loop/recursion in O(1) runtime?
Hint:
- A naive implementation of the above process is trivial. Could you come up with other methods?
- What are all the possible results?
- How do they occur, periodically or randomly?
- You may find this Wikipedia article useful.
Solution 1:
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class Solution { | |
public: | |
int addDigits(int num) { | |
int res=num; | |
while(res>=10){ | |
num=res; | |
res=0; | |
while(num>=10){ | |
res+=num%10; | |
num=num/10; | |
} | |
res=res+num; | |
} | |
return res; | |
} | |
}; |
Please check out this wiki for explanation.
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class Solution { | |
public: | |
int addDigits(int num) { | |
return num==0? 0:(num-1)%9 + 1; | |
} | |
}; |
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